<div dir="ltr">I think you have posted the problem on wrong mailing list. OpenSIPS is NOT an MCU for A/V conferences. Also whatever problem you have seems to be related to linphone, NOT opensips.<div><br></div><div>Thank you.</div>
<div><br></div></div><div class="gmail_extra"><br><br><div class="gmail_quote">On Tue, Jun 10, 2014 at 4:00 AM, CC <span dir="ltr"><<a href="mailto:liquidli@163.com" target="_blank">liquidli@163.com</a>></span> wrote:<br>
<blockquote class="gmail_quote" style="margin:0 0 0 .8ex;border-left:1px #ccc solid;padding-left:1ex"><div style="line-height:1.7;color:#000000;font-size:14px;font-family:Arial"><p class="MsoNormal"><span lang="EN-US">Hi, everyone.</span></p>
<p class="MsoNormal"><span lang="EN-US">Now I try to merge some calls into a conference,
but I have some problems. </span></p>
<p class="MsoNormal"><span lang="EN-US">The description of the problems is as
flows:</span></p>
<p class="MsoNormal"><span lang="EN-US">First</span></p>
<p class="MsoNormal"><span lang="EN-US">In the class which named
“FriendAdapter.class”, when I click the item of the listview which contains the
information of friends, I wrote a method to call the selected friend’s sip: ”</span><u><span lang="EN-US" style="font-size:10pt;font-family:'Courier New';background-color:silver;background-repeat:initial initial"> LinphoneManager</span></u><span lang="EN-US" style="font-size:10pt;font-family:'Courier New';background-color:silver;background-repeat:initial initial">.<i>getInstance</i>().callTo(sipid);</span><span lang="EN-US">”.Then in the class which named “LinphoneManager.class”, I add the
“addToConference(LinphoneCall)” in the method “callTo(String address)” .</span></p>
<p class="MsoNormal"><span lang="EN-US">Then, I try to test the function.
Connection can be established, but both the callers cannot hear to each other.
And I make a LOG message in the code to show the size of the conference and to
indicate whether the local user is part of the conference. The message shows
the size of the conference is “1” and the indication whether the local user is
part of the conference is “false”. But in the doc of Linphone, I see this:</span></p>
<p class="MsoNormal" align="left"><span lang="EN-US" style="font-family:'\00ff2d\00ff33\0030b4\0030b7\0030c3\0030af';background-color:silver;background-repeat:initial initial">void
<b>addToConference</b>(<a href="http://www.linphone.org/docs/liblinphone-javadoc/org/linphone/core/LinphoneCall.html" title="interface in org.linphone.core" target="_blank">LinphoneCall</a> call)<u></u><u></u></span></p>
<p class="MsoNormal" align="left" style="margin-left:36pt"><span lang="EN-US" style="font-family:SimSun;background-color:silver;background-repeat:initial initial">Merge a call into a conference. If this is the first call that enters
the conference, the virtual conference will be created automatically. If the
local user was actively part of the call (ie not in paused state), then the
local user is automatically entered into the conference. If the call was in
paused state, then it is automatically resumed when entering into the
conference</span><span lang="EN-US" style="font-family:SimSun">.<u></u><u></u></span></p>
<p class="MsoNormal" align="left"><span lang="EN-US">But in
my test result, the local user wasn</span><span style="font-family:"\00ff2d\00ff33\0030b4\0030b7\0030c3\0030af"">’</span><span lang="EN-US">t automatically entered into the conference. I don</span><span style="font-family:"\00ff2d\00ff33\0030b4\0030b7\0030c3\0030af"">’</span><span lang="EN-US">t know why.</span></p>
<p class="MsoNormal" align="left"><span lang="EN-US">Hope you
put forward guidance to help me solve the problems, Thank you.</span></p></div><br><br><span title="neteasefooter"><span></span></span><br>_______________________________________________<br>
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