[OpenSIPS-Users] python module - python_exec() behaviour in opensips

[Gordon Yeong]

Yeah I looked at that and ran my code on the python3 interpreter - it
worked.
Then i put it into a class - it worked.
 And then only did I put it (the class) to use in opensips..

Had there been an issue, python3 would have kicked and scream which it did
not.

 No issue with the regexp.
 Thank you

Gordon

On Sat, 16 May 2020 at 18:03, Tomi Hakkarainen <tpaivaa at gmail.com> wrote:

> Hi,
>
> not sure has this nothing to do with the error but game to my eye trying
> to figure out what this bunch of code is really doing...
>
> from python re docs:
>
> Regular expressions use the backslash character ('\') to indicate special
> forms or to allow special characters to be used without invoking their
> special meaning. This collides with Python’s usage of the same character
> for the same purpose in string literals; for example, to match a literal
> backslash, one might have to write '\\\\' as the pattern string, because
> the regular expression must be \\, and each backslash must be expressed
> as \\ inside a regular Python string literal. Also, please note that any
> invalid escape sequences in Python’s usage of the backslash in string
> literals now generate a DeprecationWarning
> <https://docs.python.org/3/library/exceptions.html#DeprecationWarning> and
> in the future this will become a SyntaxError
> <https://docs.python.org/3/library/exceptions.html#SyntaxError>. This
> behaviour will happen even if it is a valid escape sequence for a regular
> expression.
>
> The solution is to use Python’s raw string notation for regular expression
> patterns; backslashes are not handled in any special way in a string
> literal prefixed with 'r'. So r"\n" is a two-character string containing
> '\' and 'n', while "\n"is a one-character string containing a newline.
>
>
> Tomi
>
> On 16. May 2020, at 1.47, Gordon Yeong <anexiole at gmail.com> wrote:
>
> 
> It's passed the init. If i did a print (LM_ERR) In the first line of
> init(), it doesn't show that print.
>
> If i  did a print (LM_ERR)a static string   in the get_rn()  before the
> line that calls compile(), i noticed that it does print out.  And if i
> tried to print a static string right after the compile() call,  it doesn't
> print and it calls TypeError.
>
> That's why i suspect something is wrong bit can't tell exactly what....
>
>
> On Fri, 15 May 2020, 11:21 pm Ben Newlin, <Ben.Newlin at genesys.com> wrote:
>
>> Gordon,
>>
>>
>>
>> Are you sure the TypeError is not occurring in mod_init? It looks like
>> you are trying to do a print on a Class definition.
>>
>>
>>
>> Ben Newlin
>>
>>
>>
>> *From: *Users <users-bounces at lists.opensips.org> on behalf of Gordon
>> Yeong <anexiole at gmail.com>
>> *Reply-To: *OpenSIPS users mailling list <users at lists.opensips.org>
>> *Date: *Friday, May 15, 2020 at 1:54 AM
>> *To: *OpenSIPS users mailling list <users at lists.opensips.org>
>> *Subject: *[OpenSIPS-Users] python module - python_exec() behaviour in
>> opensips
>>
>>
>>
>> hi guys,
>>
>>  Using opensips 3.0 and python3 here.
>>
>>
>>
>>  I have a script which parses a number in a string
>> (r'.*rn=\+6114(\d{2})').
>>
>>
>>
>> Script is as follows:
>>
>> ---------- start ---------------
>>
>>
>>
>>
>>
>> #!/usr/bin/python3
>> import re;
>> import pprint;
>>
>>
>> class test:
>>
>>     def get_rn():
>>         rnRegExp = rnRegExp = re.compile(r'.*rn=\+6114(\d{2})');
>>         doit = rnRegExp.match( str("sip:+61386947785;npdi;rn=+
>> 611411 at tipt.ns.zippi.vocus.com;user=phone"));
>>
>>         if doit:
>>             pp = pprint.PrettyPrinter(indent=4);
>>             return doit.group(1);
>>         else:
>>             return None;
>>
>> result = test.get_rn();
>>
>> if result is None:
>>     print("Got no match\n");
>> else:
>>     print("Result is " + result);
>>
>>
>>
>> ----------- end --------------
>>
>>
>>
>> In my opensips setup, I have the function above looking like this:
>>
>>
>>
>> ---- start--------
>>
>>
>> from OpenSIPS import LM_ERR
>> import re;
>> import pprint;
>>
>> def mod_init():
>>     print("In mod_init, SIP MSG is : ");
>>     pp = pprint.PrettyPrinter(indent=4)
>>     pp.pprint(SIPMsg);
>>     return SIPMsg();
>>
>> def __init__():
>>     return 1;
>>
>> import re;
>> import pprint;
>>
>> class SIPMsg:
>>
>>     def child_init(self, rank):
>>         return 0
>>
>>     def get_rn(self, msg, raw_enum_result):
>>         try:
>>              get_rn = re.compile(r'.*rn=\+6114(\d{2})');
>>
>>              rn = get_rn.match(str(raw_enum_result));
>>              return rn.group(1);
>>         except AttributeError:
>>              # Invalid input string
>>              LM_ERR(" attribute ERRor" );
>>              return '';
>>         except TypeError:
>>              # Invalid input string
>>              LM_ERR(" Type Error" );
>>              return '';
>>         else:
>>              LM_ERR(" general ERRor" );
>>              return '';
>>
>>
>>
>> ----- end ------
>>
>>
>>
>>
>>
>>
>>
>> In my opensips config, I call the get_rn() function via python_exec() as
>> below.
>>
>>
>>
>> $var(rn_code)=python_exec("get_rn", $var(raw_string));
>>
>>
>>
>> I'm facing an issue here because when I run the script by itself in a
>> command line, it works.
>>
>>  No "Error: Text Type" but when my opensips run, it keeps hitting a
>> TypeError.
>>
>>  I have even explicitly fed the " rn =
>> get_rn.match(str(raw_enum_result));" with an explicit string (ie. I dont
>> send use the value passed in from the argument BUT instead, just feed it an
>> explicit string value) and yet the same issue occurs.
>>
>>
>>
>> Does processing control belong directly to python3 when we call
>> python_exec() or is there something funny going on here?
>>
>>
>>
>> Thank you
>>
>>
>>
>>
>>
>> Regards,
>> Gordon
>> _______________________________________________
>> Users mailing list
>> Users at lists.opensips.org
>> http://lists.opensips.org/cgi-bin/mailman/listinfo/users
>>
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